3(n+4)+2(4n-5)=5(n+2)+16

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Solution for 3(n+4)+2(4n-5)=5(n+2)+16 equation: 



3(n+4)+2(4n-5)=5(n+2)+16

We move all terms to the left:

3(n+4)+2(4n-5)-(5(n+2)+16)=0

We multiply parentheses

3n+8n-(5(n+2)+16)+12-10=0



We calculate terms in parentheses: -(5(n+2)+16), so:

5(n+2)+16

We multiply parentheses

5n+10+16

We add all the numbers together, and all the variables

5n+26

Back to the equation:

-(5n+26)



We add all the numbers together, and all the variables

11n-(5n+26)+2=0

We get rid of parentheses

11n-5n-26+2=0

We add all the numbers together, and all the variables

6n-24=0

We move all terms containing n to the left, all other terms to the right

6n=24

n=24/6

n=4

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