3(n+4)+1=3n+13

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Solution for 3(n+4)+1=3n+13 equation:


Simplifying
3(n + 4) + 1 = 3n + 13

Reorder the terms:
3(4 + n) + 1 = 3n + 13
(4 * 3 + n * 3) + 1 = 3n + 13
(12 + 3n) + 1 = 3n + 13

Reorder the terms:
12 + 1 + 3n = 3n + 13

Combine like terms: 12 + 1 = 13
13 + 3n = 3n + 13

Reorder the terms:
13 + 3n = 13 + 3n

Add '-13' to each side of the equation.
13 + -13 + 3n = 13 + -13 + 3n

Combine like terms: 13 + -13 = 0
0 + 3n = 13 + -13 + 3n
3n = 13 + -13 + 3n

Combine like terms: 13 + -13 = 0
3n = 0 + 3n
3n = 3n

Add '-3n' to each side of the equation.
3n + -3n = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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