3(n+2)=9(6-n+)

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Solution for 3(n+2)=9(6-n+) equation: 



3(n+2)=9(6-n+)

We move all terms to the left:

3(n+2)-(9(6-n+))=0

We add all the numbers together, and all the variables

3(n+2)-(9(-1n))=0

We multiply parentheses

3n-(9(-1n))+6=0



We calculate terms in parentheses: -(9(-1n)), so:

9(-1n)

We multiply parentheses

-9n

Back to the equation:

-(-9n)



We get rid of parentheses

3n+9n+6=0

We add all the numbers together, and all the variables

12n+6=0

We move all terms containing n to the left, all other terms to the right

12n=-6

n=-6/12

n=-1/2

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