3(n+2)=9(6-9)

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Solution for 3(n+2)=9(6-9) equation:



3(n+2)=9(6-9)
We move all terms to the left:
3(n+2)-(9(6-9))=0
We add all the numbers together, and all the variables
3(n+2)-(9(-3))=0
We add all the numbers together, and all the variables
3(n+2)+27=0
We multiply parentheses
3n+6+27=0
We add all the numbers together, and all the variables
3n+33=0
We move all terms containing n to the left, all other terms to the right
3n=-33
n=-33/3
n=-11

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