3(n+2)=6(9-n)

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Solution for 3(n+2)=6(9-n) equation: 



3(n+2)=6(9-n)

We move all terms to the left:

3(n+2)-(6(9-n))=0

We add all the numbers together, and all the variables

3(n+2)-(6(-1n+9))=0

We multiply parentheses

3n-(6(-1n+9))+6=0



We calculate terms in parentheses: -(6(-1n+9)), so:

6(-1n+9)

We multiply parentheses

-6n+54

Back to the equation:

-(-6n+54)



We get rid of parentheses

3n+6n-54+6=0

We add all the numbers together, and all the variables

9n-48=0

We move all terms containing n to the left, all other terms to the right

9n=48

n=48/9

n=5+1/3

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