3(n+2)=4(n+4)

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Solution for 3(n+2)=4(n+4) equation:



3(n+2)=4(n+4)
We move all terms to the left:
3(n+2)-(4(n+4))=0
We multiply parentheses
3n-(4(n+4))+6=0
We calculate terms in parentheses: -(4(n+4)), so:
4(n+4)
We multiply parentheses
4n+16
Back to the equation:
-(4n+16)
We get rid of parentheses
3n-4n-16+6=0
We add all the numbers together, and all the variables
-1n-10=0
We move all terms containing n to the left, all other terms to the right
-n=10
n=10/-1
n=-10

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