3(n+2)-7(n+7=-35

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Solution for 3(n+2)-7(n+7=-35 equation: 



3(n+2)-7(n+7=-35

We move all terms to the left:

3(n+2)-7(n+7-(-35)=0

We multiply parentheses

3n-7(n+7-(-35)+6=0

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