3(n+2)+6=4(n+3)-n

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Solution for 3(n+2)+6=4(n+3)-n equation:


Simplifying
3(n + 2) + 6 = 4(n + 3) + -1n

Reorder the terms:
3(2 + n) + 6 = 4(n + 3) + -1n
(2 * 3 + n * 3) + 6 = 4(n + 3) + -1n
(6 + 3n) + 6 = 4(n + 3) + -1n

Reorder the terms:
6 + 6 + 3n = 4(n + 3) + -1n

Combine like terms: 6 + 6 = 12
12 + 3n = 4(n + 3) + -1n

Reorder the terms:
12 + 3n = 4(3 + n) + -1n
12 + 3n = (3 * 4 + n * 4) + -1n
12 + 3n = (12 + 4n) + -1n

Combine like terms: 4n + -1n = 3n
12 + 3n = 12 + 3n

Add '-12' to each side of the equation.
12 + -12 + 3n = 12 + -12 + 3n

Combine like terms: 12 + -12 = 0
0 + 3n = 12 + -12 + 3n
3n = 12 + -12 + 3n

Combine like terms: 12 + -12 = 0
3n = 0 + 3n
3n = 3n

Add '-3n' to each side of the equation.
3n + -3n = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 3n + -3n

Combine like terms: 3n + -3n = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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