3(n+2)+5(n-2)=12

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Solution for 3(n+2)+5(n-2)=12 equation: 



3(n+2)+5(n-2)=12

We move all terms to the left:

3(n+2)+5(n-2)-(12)=0

We multiply parentheses

3n+5n+6-10-12=0

We add all the numbers together, and all the variables

8n-16=0

We move all terms containing n to the left, all other terms to the right

8n=16

n=16/8

n=2

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