3(n+2)+4=19

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Solution for 3(n+2)+4=19 equation: 



3(n+2)+4=19

We move all terms to the left:

3(n+2)+4-(19)=0

We add all the numbers together, and all the variables

3(n+2)-15=0

We multiply parentheses

3n+6-15=0

We add all the numbers together, and all the variables

3n-9=0

We move all terms containing n to the left, all other terms to the right

3n=9

n=9/3

n=3

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