3(n+1)/4=5(n-2)/6-2

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Solution for 3(n+1)/4=5(n-2)/6-2 equation: 



3(n+1)/4=5(n-2)/6-2

We move all terms to the left:

3(n+1)/4-(5(n-2)/6-2)=0

We calculate fractions


(18n+18)/()+(-(5(n-2)*4)/()=0



We calculate terms in parentheses: +(-(5(n-2)*4)/(), so:

-(5(n-2)*4)/(

We multiply all the terms by the denominator


-(5(n-2)*4)



We calculate terms in parentheses: -(5(n-2)*4), so:

5(n-2)*4

We multiply parentheses

20n-40

Back to the equation:

-(20n-40)



We get rid of parentheses

-20n+40

Back to the equation:

+(-20n+40)



We get rid of parentheses

(18n+18)/()-20n+40=0

We multiply all the terms by the denominator


(18n+18)-20n*()+40*()=0

We add all the numbers together, and all the variables

(18n+18)-20n*()=0

We get rid of parentheses

18n-20n*()+18=0

We move all terms containing n to the left, all other terms to the right

18n-20n*()=-18

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