3(m-2)+2m=19

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Solution for 3(m-2)+2m=19 equation: 



3(m-2)+2m=19

We move all terms to the left:

3(m-2)+2m-(19)=0

We add all the numbers together, and all the variables

2m+3(m-2)-19=0

We multiply parentheses

2m+3m-6-19=0

We add all the numbers together, and all the variables

5m-25=0

We move all terms containing m to the left, all other terms to the right

5m=25

m=25/5

m=5

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