3(m+3)-7=2(m-4)

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Solution for 3(m+3)-7=2(m-4) equation: 



3(m+3)-7=2(m-4)

We move all terms to the left:

3(m+3)-7-(2(m-4))=0

We multiply parentheses

3m-(2(m-4))+9-7=0



We calculate terms in parentheses: -(2(m-4)), so:

2(m-4)

We multiply parentheses

2m-8

Back to the equation:

-(2m-8)



We add all the numbers together, and all the variables

3m-(2m-8)+2=0

We get rid of parentheses

3m-2m+8+2=0

We add all the numbers together, and all the variables

m+10=0

We move all terms containing m to the left, all other terms to the right

m=-10

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