3(m+3)-4(-2+m)=19

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Solution for 3(m+3)-4(-2+m)=19 equation: 



3(m+3)-4(-2+m)=19

We move all terms to the left:

3(m+3)-4(-2+m)-(19)=0

We add all the numbers together, and all the variables

3(m+3)-4(m-2)-19=0

We multiply parentheses

3m-4m+9+8-19=0

We add all the numbers together, and all the variables

-1m-2=0

We move all terms containing m to the left, all other terms to the right

-m=2

m=2/-1

m=-2

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