3(m+2)=6(n-1)

Solution for 3(m+2)=6(n-1) equation:

Simplifying
3(m + 2) = 6(n + -1)

Reorder the terms:
3(2 + m) = 6(n + -1)
(2 * 3 + m * 3) = 6(n + -1)
(6 + 3m) = 6(n + -1)

Reorder the terms:
6 + 3m = 6(-1 + n)
6 + 3m = (-1 * 6 + n * 6)
6 + 3m = (-6 + 6n)

Solving
6 + 3m = -6 + 6n

Solving for variable 'm'.

Move all terms containing m to the left, all other terms to the right.

Add '-6' to each side of the equation.
6 + -6 + 3m = -6 + -6 + 6n

Combine like terms: 6 + -6 = 0
0 + 3m = -6 + -6 + 6n
3m = -6 + -6 + 6n

Combine like terms: -6 + -6 = -12
3m = -12 + 6n

Divide each side by '3'.
m = -4 + 2n

Simplifying
m = -4 + 2n