3(m+2)-m=2(m+1)

Solution for 3(m+2)-m=2(m+1) equation:

3(m+2)-m=2(m+1)

We move all terms to the left:

3(m+2)-m-(2(m+1))=0

We add all the numbers together, and all the variables

-1m+3(m+2)-(2(m+1))=0

We multiply parentheses

-1m+3m-(2(m+1))+6=0


We calculate terms in parentheses: -(2(m+1)), so:

2(m+1)

We multiply parentheses

2m+2

Back to the equation:

-(2m+2)


We add all the numbers together, and all the variables

2m-(2m+2)+6=0

We get rid of parentheses

2m-2m-2+6=0

We add all the numbers together, and all the variables

4!=0

There is no solution for this equation