3(m+1)=17+m-12

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Solution for 3(m+1)=17+m-12 equation:



3(m+1)=17+m-12
We move all terms to the left:
3(m+1)-(17+m-12)=0
We add all the numbers together, and all the variables
3(m+1)-(m+5)=0
We multiply parentheses
3m-(m+5)+3=0
We get rid of parentheses
3m-m-5+3=0
We add all the numbers together, and all the variables
2m-2=0
We move all terms containing m to the left, all other terms to the right
2m=2
m=2/2
m=1

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