3(log(2x+4))=x+1

Solution for 3(log(2x+4))=x+1 equation:

Simplifying
3(log(2x + 4)) = x + 1

Reorder the terms:
3(glo(4 + 2x)) = x + 1
3((4 * glo + 2x * glo)) = x + 1
3((4glo + 2glox)) = x + 1
(4glo * 3 + 2glox * 3) = x + 1
(12glo + 6glox) = x + 1

Reorder the terms:
12glo + 6glox = 1 + x

Solving
12glo + 6glox = 1 + x

Solving for variable 'g'.

Move all terms containing g to the left, all other terms to the right.

Reorder the terms:
-1 + 12glo + 6glox + -1x = 1 + x + -1 + -1x

Reorder the terms:
-1 + 12glo + 6glox + -1x = 1 + -1 + x + -1x

Combine like terms: 1 + -1 = 0
-1 + 12glo + 6glox + -1x = 0 + x + -1x
-1 + 12glo + 6glox + -1x = x + -1x

Combine like terms: x + -1x = 0
-1 + 12glo + 6glox + -1x = 0

The solution to this equation could not be determined.