3(k-9)=k+5

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Solution for 3(k-9)=k+5 equation: 



3(k-9)=k+5

We move all terms to the left:

3(k-9)-(k+5)=0

We multiply parentheses

3k-(k+5)-27=0

We get rid of parentheses

3k-k-5-27=0

We add all the numbers together, and all the variables

2k-32=0

We move all terms containing k to the left, all other terms to the right

2k=32

k=32/2

k=16

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