3(k-6)-(2k-5)=7

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Solution for 3(k-6)-(2k-5)=7 equation: 



3(k-6)-(2k-5)=7

We move all terms to the left:

3(k-6)-(2k-5)-(7)=0

We multiply parentheses

3k-(2k-5)-18-7=0

We get rid of parentheses

3k-2k+5-18-7=0

We add all the numbers together, and all the variables

k-20=0

We move all terms containing k to the left, all other terms to the right

k=20

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