3(k-5)=-2(k-6)

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Solution for 3(k-5)=-2(k-6) equation: 



3(k-5)=-2(k-6)

We move all terms to the left:

3(k-5)-(-2(k-6))=0

We multiply parentheses

3k-(-2(k-6))-15=0



We calculate terms in parentheses: -(-2(k-6)), so:

-2(k-6)

We multiply parentheses

-2k+12

Back to the equation:

-(-2k+12)



We get rid of parentheses

3k+2k-12-15=0

We add all the numbers together, and all the variables

5k-27=0

We move all terms containing k to the left, all other terms to the right

5k=27

k=27/5

k=5+2/5

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