3(k-5)-2(k+2)-13=-25

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Solution for 3(k-5)-2(k+2)-13=-25 equation: 


Simplifying
3(k + -5) + -2(k + 2) + -13 = -25

Reorder the terms:
3(-5 + k) + -2(k + 2) + -13 = -25
(-5 * 3 + k * 3) + -2(k + 2) + -13 = -25
(-15 + 3k) + -2(k + 2) + -13 = -25

Reorder the terms:
-15 + 3k + -2(2 + k) + -13 = -25
-15 + 3k + (2 * -2 + k * -2) + -13 = -25
-15 + 3k + (-4 + -2k) + -13 = -25

Reorder the terms:
-15 + -4 + -13 + 3k + -2k = -25

Combine like terms: -15 + -4 = -19
-19 + -13 + 3k + -2k = -25

Combine like terms: -19 + -13 = -32
-32 + 3k + -2k = -25

Combine like terms: 3k + -2k = 1k
-32 + 1k = -25

Solving
-32 + 1k = -25

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '32' to each side of the equation.
-32 + 32 + 1k = -25 + 32

Combine like terms: -32 + 32 = 0
0 + 1k = -25 + 32
1k = -25 + 32

Combine like terms: -25 + 32 = 7
1k = 7

Divide each side by '1'.
k = 7

Simplifying
k = 7

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