3(k-4)=2(k+3)

Solution for 3(k-4)=2(k+3) equation:

Simplifying
3(k + -4) = 2(k + 3)

Reorder the terms:
3(-4 + k) = 2(k + 3)
(-4 * 3 + k * 3) = 2(k + 3)
(-12 + 3k) = 2(k + 3)

Reorder the terms:
-12 + 3k = 2(3 + k)
-12 + 3k = (3 * 2 + k * 2)
-12 + 3k = (6 + 2k)

Solving
-12 + 3k = 6 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-12 + 3k + -2k = 6 + 2k + -2k

Combine like terms: 3k + -2k = 1k
-12 + 1k = 6 + 2k + -2k

Combine like terms: 2k + -2k = 0
-12 + 1k = 6 + 0
-12 + 1k = 6

Add '12' to each side of the equation.
-12 + 12 + 1k = 6 + 12

Combine like terms: -12 + 12 = 0
0 + 1k = 6 + 12
1k = 6 + 12

Combine like terms: 6 + 12 = 18
1k = 18

Divide each side by '1'.
k = 18

Simplifying
k = 18