3(k-4)=1/2(4K-16

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Solution for 3(k-4)=1/2(4K-16 equation: 



3(k-4)=1/2(4-16

We move all terms to the left:

3(k-4)-(1/2(4-16)=0

We add all the numbers together, and all the variables

3(k-4)-(1/2(-12)=0

We multiply parentheses

3k-12-(1/2(-12)=0

We multiply all the terms by the denominator


3k*2(-12)-12*2(-12)-(1=0

We add all the numbers together, and all the variables

3k*2(-12)=0

Wy multiply elements

6k^2(-=0

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