3(k-4)+3k=k+3

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Solution for 3(k-4)+3k=k+3 equation: 



3(k-4)+3k=k+3

We move all terms to the left:

3(k-4)+3k-(k+3)=0

We add all the numbers together, and all the variables

3k+3(k-4)-(k+3)=0

We multiply parentheses

3k+3k-(k+3)-12=0

We get rid of parentheses

3k+3k-k-3-12=0

We add all the numbers together, and all the variables

5k-15=0

We move all terms containing k to the left, all other terms to the right

5k=15

k=15/5

k=3

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