3(k-3)-5=3k-(2k-1)

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Solution for 3(k-3)-5=3k-(2k-1) equation: 


Simplifying
3(k + -3) + -5 = 3k + -1(2k + -1)

Reorder the terms:
3(-3 + k) + -5 = 3k + -1(2k + -1)
(-3 * 3 + k * 3) + -5 = 3k + -1(2k + -1)
(-9 + 3k) + -5 = 3k + -1(2k + -1)

Reorder the terms:
-9 + -5 + 3k = 3k + -1(2k + -1)

Combine like terms: -9 + -5 = -14
-14 + 3k = 3k + -1(2k + -1)

Reorder the terms:
-14 + 3k = 3k + -1(-1 + 2k)
-14 + 3k = 3k + (-1 * -1 + 2k * -1)
-14 + 3k = 3k + (1 + -2k)

Reorder the terms:
-14 + 3k = 1 + 3k + -2k

Combine like terms: 3k + -2k = 1k
-14 + 3k = 1 + 1k

Solving
-14 + 3k = 1 + 1k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-1k' to each side of the equation.
-14 + 3k + -1k = 1 + 1k + -1k

Combine like terms: 3k + -1k = 2k
-14 + 2k = 1 + 1k + -1k

Combine like terms: 1k + -1k = 0
-14 + 2k = 1 + 0
-14 + 2k = 1

Add '14' to each side of the equation.
-14 + 14 + 2k = 1 + 14

Combine like terms: -14 + 14 = 0
0 + 2k = 1 + 14
2k = 1 + 14

Combine like terms: 1 + 14 = 15
2k = 15

Divide each side by '2'.
k = 7.5

Simplifying
k = 7.5

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