3(k-2)=3k-12

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Solution for 3(k-2)=3k-12 equation: 



3(k-2)=3k-12

We move all terms to the left:

3(k-2)-(3k-12)=0

We multiply parentheses

3k-(3k-12)-6=0

We get rid of parentheses

3k-3k+12-6=0

We add all the numbers together, and all the variables

6!=0

There is no solution for this equation

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