3(k-2)=2(k-5)

Solution for 3(k-2)=2(k-5) equation:

Simplifying
3(k + -2) = 2(k + -5)

Reorder the terms:
3(-2 + k) = 2(k + -5)
(-2 * 3 + k * 3) = 2(k + -5)
(-6 + 3k) = 2(k + -5)

Reorder the terms:
-6 + 3k = 2(-5 + k)
-6 + 3k = (-5 * 2 + k * 2)
-6 + 3k = (-10 + 2k)

Solving
-6 + 3k = -10 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
-6 + 3k + -2k = -10 + 2k + -2k

Combine like terms: 3k + -2k = 1k
-6 + 1k = -10 + 2k + -2k

Combine like terms: 2k + -2k = 0
-6 + 1k = -10 + 0
-6 + 1k = -10

Add '6' to each side of the equation.
-6 + 6 + 1k = -10 + 6

Combine like terms: -6 + 6 = 0
0 + 1k = -10 + 6
1k = -10 + 6

Combine like terms: -10 + 6 = -4
1k = -4

Divide each side by '1'.
k = -4

Simplifying
k = -4