3(k-2)+2k=2(2k+1)+5

Solution for 3(k-2)+2k=2(2k+1)+5 equation:

Simplifying
3(k + -2) + 2k = 2(2k + 1) + 5

Reorder the terms:
3(-2 + k) + 2k = 2(2k + 1) + 5
(-2 * 3 + k * 3) + 2k = 2(2k + 1) + 5
(-6 + 3k) + 2k = 2(2k + 1) + 5

Combine like terms: 3k + 2k = 5k
-6 + 5k = 2(2k + 1) + 5

Reorder the terms:
-6 + 5k = 2(1 + 2k) + 5
-6 + 5k = (1 * 2 + 2k * 2) + 5
-6 + 5k = (2 + 4k) + 5

Reorder the terms:
-6 + 5k = 2 + 5 + 4k

Combine like terms: 2 + 5 = 7
-6 + 5k = 7 + 4k

Solving
-6 + 5k = 7 + 4k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-4k' to each side of the equation.
-6 + 5k + -4k = 7 + 4k + -4k

Combine like terms: 5k + -4k = 1k
-6 + 1k = 7 + 4k + -4k

Combine like terms: 4k + -4k = 0
-6 + 1k = 7 + 0
-6 + 1k = 7

Add '6' to each side of the equation.
-6 + 6 + 1k = 7 + 6

Combine like terms: -6 + 6 = 0
0 + 1k = 7 + 6
1k = 7 + 6

Combine like terms: 7 + 6 = 13
1k = 13

Divide each side by '1'.
k = 13

Simplifying
k = 13