3(k+5)=-2(3k+-6)

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Solution for 3(k+5)=-2(3k+-6) equation: 



3(k+5)=-2(3k+-6)

We move all terms to the left:

3(k+5)-(-2(3k+-6))=0

We add all the numbers together, and all the variables

3(k+5)-(-2(3k-6))=0

We multiply parentheses

3k-(-2(3k-6))+15=0



We calculate terms in parentheses: -(-2(3k-6)), so:

-2(3k-6)

We multiply parentheses

-6k+12

Back to the equation:

-(-6k+12)



We get rid of parentheses

3k+6k-12+15=0

We add all the numbers together, and all the variables

9k+3=0

We move all terms containing k to the left, all other terms to the right

9k=-3

k=-3/9

k=-1/3

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