3(k+5)=-2(2k-6)

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Solution for 3(k+5)=-2(2k-6) equation: 



3(k+5)=-2(2k-6)

We move all terms to the left:

3(k+5)-(-2(2k-6))=0

We multiply parentheses

3k-(-2(2k-6))+15=0



We calculate terms in parentheses: -(-2(2k-6)), so:

-2(2k-6)

We multiply parentheses

-4k+12

Back to the equation:

-(-4k+12)



We get rid of parentheses

3k+4k-12+15=0

We add all the numbers together, and all the variables

7k+3=0

We move all terms containing k to the left, all other terms to the right

7k=-3

k=-3/7

k=-3/7

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