3(k+5)=-(3k-6)

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Solution for 3(k+5)=-(3k-6) equation: 



3(k+5)=-(3k-6)

We move all terms to the left:

3(k+5)-(-(3k-6))=0

We multiply parentheses

3k-(-(3k-6))+15=0



We calculate terms in parentheses: -(-(3k-6)), so:

-(3k-6)

We get rid of parentheses

-3k+6

Back to the equation:

-(-3k+6)



We get rid of parentheses

3k+3k-6+15=0

We add all the numbers together, and all the variables

6k+9=0

We move all terms containing k to the left, all other terms to the right

6k=-9

k=-9/6

k=-1+1/2

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