3(k+4)=k+16

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Solution for 3(k+4)=k+16 equation: 



3(k+4)=k+16

We move all terms to the left:

3(k+4)-(k+16)=0

We multiply parentheses

3k-(k+16)+12=0

We get rid of parentheses

3k-k-16+12=0

We add all the numbers together, and all the variables

2k-4=0

We move all terms containing k to the left, all other terms to the right

2k=4

k=4/2

k=2

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