3(k+3)=6k+18

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Solution for 3(k+3)=6k+18 equation: 



3(k+3)=6k+18

We move all terms to the left:

3(k+3)-(6k+18)=0

We multiply parentheses

3k-(6k+18)+9=0

We get rid of parentheses

3k-6k-18+9=0

We add all the numbers together, and all the variables

-3k-9=0

We move all terms containing k to the left, all other terms to the right

-3k=9

k=9/-3

k=-3

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