3(k+2)=2k+9

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Solution for 3(k+2)=2k+9 equation: 



3(k+2)=2k+9

We move all terms to the left:

3(k+2)-(2k+9)=0

We multiply parentheses

3k-(2k+9)+6=0

We get rid of parentheses

3k-2k-9+6=0

We add all the numbers together, and all the variables

k-3=0

We move all terms containing k to the left, all other terms to the right

k=3

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