3(k+2)+7k=2(5k+3)

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Solution for 3(k+2)+7k=2(5k+3) equation: 



3(k+2)+7k=2(5k+3)

We move all terms to the left:

3(k+2)+7k-(2(5k+3))=0

We add all the numbers together, and all the variables

7k+3(k+2)-(2(5k+3))=0

We multiply parentheses

7k+3k-(2(5k+3))+6=0



We calculate terms in parentheses: -(2(5k+3)), so:

2(5k+3)

We multiply parentheses

10k+6

Back to the equation:

-(10k+6)



We add all the numbers together, and all the variables

10k-(10k+6)+6=0

We get rid of parentheses

10k-10k-6+6=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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