3(k+2)+1=10

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Solution for 3(k+2)+1=10 equation: 



3(k+2)+1=10

We move all terms to the left:

3(k+2)+1-(10)=0

We add all the numbers together, and all the variables

3(k+2)-9=0

We multiply parentheses

3k+6-9=0

We add all the numbers together, and all the variables

3k-3=0

We move all terms containing k to the left, all other terms to the right

3k=3

k=3/3

k=1

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