3(k+14)=12k-6(9k-7)

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Solution for 3(k+14)=12k-6(9k-7) equation: 



3(k+14)=12k-6(9k-7)

We move all terms to the left:

3(k+14)-(12k-6(9k-7))=0

We multiply parentheses

3k-(12k-6(9k-7))+42=0



We calculate terms in parentheses: -(12k-6(9k-7)), so:

12k-6(9k-7)

We multiply parentheses

12k-54k+42

We add all the numbers together, and all the variables

-42k+42

Back to the equation:

-(-42k+42)



We get rid of parentheses

3k+42k-42+42=0

We add all the numbers together, and all the variables

45k=0

k=0/45

k=0

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