3(k+1)=2(k-5)

Solution for 3(k+1)=2(k-5) equation:

Simplifying
3(k + 1) = 2(k + -5)

Reorder the terms:
3(1 + k) = 2(k + -5)
(1 * 3 + k * 3) = 2(k + -5)
(3 + 3k) = 2(k + -5)

Reorder the terms:
3 + 3k = 2(-5 + k)
3 + 3k = (-5 * 2 + k * 2)
3 + 3k = (-10 + 2k)

Solving
3 + 3k = -10 + 2k

Solving for variable 'k'.

Move all terms containing k to the left, all other terms to the right.

Add '-2k' to each side of the equation.
3 + 3k + -2k = -10 + 2k + -2k

Combine like terms: 3k + -2k = 1k
3 + 1k = -10 + 2k + -2k

Combine like terms: 2k + -2k = 0
3 + 1k = -10 + 0
3 + 1k = -10

Add '-3' to each side of the equation.
3 + -3 + 1k = -10 + -3

Combine like terms: 3 + -3 = 0
0 + 1k = -10 + -3
1k = -10 + -3

Combine like terms: -10 + -3 = -13
1k = -13

Divide each side by '1'.
k = -13

Simplifying
k = -13