3(k+1)+11k=2(4+5k)=3

Solution for 3(k+1)+11k=2(4+5k)=3 equation:

3(k+1)+11k=2(4+5k)=3

We move all terms to the left:

3(k+1)+11k-(2(4+5k))=0

We add all the numbers together, and all the variables

3(k+1)+11k-(2(5k+4))=0

We add all the numbers together, and all the variables

11k+3(k+1)-(2(5k+4))=0

We multiply parentheses

11k+3k-(2(5k+4))+3=0


We calculate terms in parentheses: -(2(5k+4)), so:

2(5k+4)

We multiply parentheses

10k+8

Back to the equation:

-(10k+8)


We add all the numbers together, and all the variables

14k-(10k+8)+3=0

We get rid of parentheses

14k-10k-8+3=0

We add all the numbers together, and all the variables

4k-5=0

We move all terms containing k to the left, all other terms to the right

4k=5

k=5/4

k=1+1/4