3(j-72)=12

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Solution for 3(j-72)=12 equation: 



3(j-72)=12

We move all terms to the left:

3(j-72)-(12)=0

We multiply parentheses

3j-216-12=0

We add all the numbers together, and all the variables

3j-228=0

We move all terms containing j to the left, all other terms to the right

3j=228

j=228/3

j=76

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