3(j-5)=5(11-j)

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Solution for 3(j-5)=5(11-j) equation: 



3(j-5)=5(11-j)

We move all terms to the left:

3(j-5)-(5(11-j))=0

We add all the numbers together, and all the variables

3(j-5)-(5(-1j+11))=0

We multiply parentheses

3j-(5(-1j+11))-15=0



We calculate terms in parentheses: -(5(-1j+11)), so:

5(-1j+11)

We multiply parentheses

-5j+55

Back to the equation:

-(-5j+55)



We get rid of parentheses

3j+5j-55-15=0

We add all the numbers together, and all the variables

8j-70=0

We move all terms containing j to the left, all other terms to the right

8j=70

j=70/8

j=8+3/4

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