3(j+2)=2(2j-1)

Solution for 3(j+2)=2(2j-1) equation:

Simplifying
3(j + 2) = 2(2j + -1)

Reorder the terms:
3(2 + j) = 2(2j + -1)
(2 * 3 + j * 3) = 2(2j + -1)
(6 + 3j) = 2(2j + -1)

Reorder the terms:
6 + 3j = 2(-1 + 2j)
6 + 3j = (-1 * 2 + 2j * 2)
6 + 3j = (-2 + 4j)

Solving
6 + 3j = -2 + 4j

Solving for variable 'j'.

Move all terms containing j to the left, all other terms to the right.

Add '-4j' to each side of the equation.
6 + 3j + -4j = -2 + 4j + -4j

Combine like terms: 3j + -4j = -1j
6 + -1j = -2 + 4j + -4j

Combine like terms: 4j + -4j = 0
6 + -1j = -2 + 0
6 + -1j = -2

Add '-6' to each side of the equation.
6 + -6 + -1j = -2 + -6

Combine like terms: 6 + -6 = 0
0 + -1j = -2 + -6
-1j = -2 + -6

Combine like terms: -2 + -6 = -8
-1j = -8

Divide each side by '-1'.
j = 8

Simplifying
j = 8