3(j+2)+4=28

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Solution for 3(j+2)+4=28 equation: 



3(j+2)+4=28

We move all terms to the left:

3(j+2)+4-(28)=0

We add all the numbers together, and all the variables

3(j+2)-24=0

We multiply parentheses

3j+6-24=0

We add all the numbers together, and all the variables

3j-18=0

We move all terms containing j to the left, all other terms to the right

3j=18

j=18/3

j=6

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