3(i-10)=27

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Solution for 3(i-10)=27 equation: 



3(i-10)=27

We move all terms to the left:

3(i-10)-(27)=0

We multiply parentheses

3i-30-27=0

We add all the numbers together, and all the variables

3i-57=0

We move all terms containing i to the left, all other terms to the right

3i=57

i=57/3

i=19

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