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3(h-6)=2(-2h+5)
We move all terms to the left:
3(h-6)-(2(-2h+5))=0
We multiply parentheses
3h-(2(-2h+5))-18=0
We calculate terms in parentheses: -(2(-2h+5)), so:We get rid of parentheses
2(-2h+5)
We multiply parentheses
-4h+10
Back to the equation:
-(-4h+10)
3h+4h-10-18=0
We add all the numbers together, and all the variables
7h-28=0
We move all terms containing h to the left, all other terms to the right
7h=28
h=28/7
h=4
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