3(h+3)=2(h+10)

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Solution for 3(h+3)=2(h+10) equation: 



3(h+3)=2(h+10)

We move all terms to the left:

3(h+3)-(2(h+10))=0

We multiply parentheses

3h-(2(h+10))+9=0



We calculate terms in parentheses: -(2(h+10)), so:

2(h+10)

We multiply parentheses

2h+20

Back to the equation:

-(2h+20)



We get rid of parentheses

3h-2h-20+9=0

We add all the numbers together, and all the variables

h-11=0

We move all terms containing h to the left, all other terms to the right

h=11

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