3(h+2)-h=h+16

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Solution for 3(h+2)-h=h+16 equation:



3(h+2)-h=h+16
We move all terms to the left:
3(h+2)-h-(h+16)=0
We add all the numbers together, and all the variables
-1h+3(h+2)-(h+16)=0
We multiply parentheses
-1h+3h-(h+16)+6=0
We get rid of parentheses
-1h+3h-h-16+6=0
We add all the numbers together, and all the variables
h-10=0
We move all terms containing h to the left, all other terms to the right
h=10

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