3(h+2)-4(h-10)=42

Solution for 3(h+2)-4(h-10)=42 equation:

Simplifying
3(h + 2) + -4(h + -10) = 42

Reorder the terms:
3(2 + h) + -4(h + -10) = 42
(2 * 3 + h * 3) + -4(h + -10) = 42
(6 + 3h) + -4(h + -10) = 42

Reorder the terms:
6 + 3h + -4(-10 + h) = 42
6 + 3h + (-10 * -4 + h * -4) = 42
6 + 3h + (40 + -4h) = 42

Reorder the terms:
6 + 40 + 3h + -4h = 42

Combine like terms: 6 + 40 = 46
46 + 3h + -4h = 42

Combine like terms: 3h + -4h = -1h
46 + -1h = 42

Solving
46 + -1h = 42

Solving for variable 'h'.

Move all terms containing h to the left, all other terms to the right.

Add '-46' to each side of the equation.
46 + -46 + -1h = 42 + -46

Combine like terms: 46 + -46 = 0
0 + -1h = 42 + -46
-1h = 42 + -46

Combine like terms: 42 + -46 = -4
-1h = -4

Divide each side by '-1'.
h = 4

Simplifying
h = 4