3(g-5)+4=-g+19+2g

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Solution for 3(g-5)+4=-g+19+2g equation: 



3(g-5)+4=-g+19+2g

We move all terms to the left:

3(g-5)+4-(-g+19+2g)=0

We add all the numbers together, and all the variables

3(g-5)-(g+19)+4=0

We multiply parentheses

3g-(g+19)-15+4=0

We get rid of parentheses

3g-g-19-15+4=0

We add all the numbers together, and all the variables

2g-30=0

We move all terms containing g to the left, all other terms to the right

2g=30

g=30/2

g=15

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